推 roud:我白癡了.... 謝謝~ 06/17 22:22
※ 引述《roud (對愛絕望)》之銘言:
: 題目:
: 1 + (xy)^2 + y + xy' = 0
: -1
: ans: tan (xy) + x = C
: 感謝~
dx + (xy)^2 dx +ydx +xdy = 0
=> [1+(xy)^2] dx + d(xy) = 0
變數分離
=> dx + [1+(xy)^2]^(-1) d(xy) = 0
兩邊積分
=> x + arctan(xy) = C
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