A given computer has 16bit instruction. Operand address are specified
using 6bit field. There are 13 two-operand instructiond and 13
zero-operand instructions required. What is the maximum number of one-operand
instruction the can be provided in this computer ?
(A)192 (B)191 (C)64 (D)63
答案給B
我的解法...
(2^4-13)*6^2-13 = 95
想請問這題正確的解法 謝謝
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