推 GamesWang:Ax=b有超過一解→無限多解→rank(A) < n 10/13 23:37
→ GamesWang:表A為singular→Ax=0存在非零解 10/13 23:39
→ GamesWang:此非零解倍數均為Ax=0之解ex: A(qx)=(q0)=0 q為純量 10/13 23:41
→ milicic2103:我好像卡在不知道A為singular~~請問怎推 謝謝 10/13 23:50
推 GamesWang:因為rank(A)!=n所以不為nonsingular→A為singular 10/14 00:18
推 hunter0904:正解 觀念好! 10/14 07:32
推 mqazz1:推這篇 10/14 12:40