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※ 引述《e761031 ()》之銘言: : 想請教一題An+2-4An+1+3An=0 A_(n+2) - 4 A_(n+1) + 3 A_n = 0 => [A_(n+2) - A_(n+1)] = 3 [A_(n+1) - A_n] Or [A_(n+2) - 3A_(n+1)] = [A_(n+1) - 3A_n] : 請問An要怎麼求? : THX -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 69.143.35.105
e761031:感謝!! 11/11 18:58