推 e761031:感謝!! 11/11 18:58
※ 引述《e761031 ()》之銘言:
: 想請教一題An+2-4An+1+3An=0
A_(n+2) - 4 A_(n+1) + 3 A_n = 0
=> [A_(n+2) - A_(n+1)] = 3 [A_(n+1) - A_n]
Or [A_(n+2) - 3A_(n+1)] = [A_(n+1) - 3A_n]
: 請問An要怎麼求?
: THX
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