作者mqazz1 (無法顯示)
看板Grad-ProbAsk
標題[理工] [離散]-92清大-資應所
時間Sun Nov 21 21:28:22 2010
determine the number of ways to distribute 2t+1 indistinguishable coins to
three boys so that
any two boys together will have more coins that the other one
請問這題用排列組合要怎麼解?
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推 cakeboy:不知道可不可以x1+x2+x3=2t+1 x1<x2<=x3 11/21 21:44
推 hunter0904:任兩個都不會比對方多嗎? that是than嗎? 11/22 00:09
→ hunter0904:這樣X1會=X2=X3??? 11/22 00:10
→ hunter0904:看錯了= = 11/22 00:11
推 juan19283746:應該就是三個的範圍都介在1~t 然後相加=2t+1 11/22 00:11
→ qk211:我跟樓上想的一樣 11/22 02:05