看板 Grad-ProbAsk 關於我們 聯絡資訊
http://www.lib.ntu.edu.tw/exam/graduate/97/97419.pdf 第二題的(d)小題 張凡的解答寫 (100-x)/(0.5*8) = x 請問這個式子要怎麼解釋?? 爬文之後發現問題似乎是出在這一句敘述 for an 8-processor run, 50% of time a processor has to stall because the processor is waiting to access the disk 我自己的解釋是這樣 (run_CPU_time + I/O_time) = 100 I/O_time = x total_CPU_time = run_CPU_time_8pro + stall_CPU_time stall_CPU_time = 50%*total_CPU_time = run_CPU_time_8pro total_CPU_time = run_CPU_time_8pro/(0.5) run_CPU_time = 100-x run_CPU_time_8pro = (100-x)/8 total_CPU_time = (100-x)/(0.5*8) 如果是這樣 那題目中有哪一句提到total_CPU_time = I/O_time 呢? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.30.96
tetragramm:你爬文的那句話不就說了嗎!? 01/02 16:01
nypgand1:我的50%是用在 stall_CPU_time = 50%*total_CPU_time 01/02 16:08
nypgand1:如果題目的意思是total_CPU_time = I/O_time 01/02 16:09
nypgand1:那(100-x)/(0.5*8)=x 左式除的0.5就需要另外的解釋了 01/02 16:10