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p: page fault ratio q: modified ratio EAT = (1-p)*(memory access time) + p*( q * cond1 + (1-q)* cond2 + memory access time) - (1) ^^^^^^^^^^^^^^ 與Cond1, Cond2比太小 = memory access time + p * (q *cond1 + (1-q)*cond2) - (2) (1)若(1)可省去page fault時的memory access time,則得 EAT = (1-p)*(memory access time) + p*(q*cond + (1-q)*cond2) -(3) (3)式為原原po之答案 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.126.187.85
kai5566:謝謝回答! 那其實1式不就是把mem access前的(1-p)去掉 01/19 18:01
kai5566:感覺答案加上(1-p)有點多此一舉耶~ 01/19 18:02