: 2x^2y'+6xy-x^3y+1=0
2x^2dy+6xydx-x^3ydx+dx=0
2x(xdy+3ydx)+(1-x^3y)dx=0
2x^-1d(x^3y)+(1-x^3y)dx=0
-2(x^3y-1)^-1d(x^3y-1)+xdx=0
(x^3y-1)^-2=ce^(-1/2)x^2
x^3y=Ce^(√1/2)x+1
y=x^-3(Ce^(√1/2)x+1)
差不多是這樣 有錯請指證
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※ 編輯: Geforcesaori 來自: 114.33.241.155 (02/01 17:22)