看板 Grad-ProbAsk 關於我們 聯絡資訊
98交大資聯 線代 5.選對的 (c) Let P3 be the space consisting of all polynomial of degree no more than 3, and D be the differetiation operator on P3 . Then, ker(D) = {0}. 這選項是錯的 有板友能提供一點想法嗎? 感謝 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.248.224.211
ybite:p(x) = 5為一多項式,且其微分過後為0 02/11 16:01
ybite:我另有想法:如果以{1,x,x^2,x^3}為Basis,微分應該可表為 02/11 16:02
ybite:一個矩陣, [ 0 1 0 0 ] 02/11 16:03
ybite: [ 0 0 2 0 ] 02/11 16:03
ybite: [ 0 0 0 3 ],其nullity=1,因此ker(D)!=0(歪了XD 02/11 16:03
ybite: [ 0 0 0 0 ] 02/11 16:04
BenLinus:同意樓上! 02/11 16:44
peropero1:由定義:ker(D)={x|D(x)=0,x屬於P3}, 02/11 17:35
peropero1:所以x需為常數才成立 所以ker(D)!=0 02/11 17:35
SkullMaster:我了解了,謝謝各位板指教:) 02/11 17:43