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※ 引述《compulsory (まけない!)》之銘言: : suppose that v,w,z are vector in R^n such that v is orthogonal to z and z is : orthogonal to w. Then : (a)For any orthogonal n*n matrix H,we have that Hz is orthogonal to both v & w : (b)v+w is orthogonal to z : (c)v is orthogonal to w : (d)For any orthogonal n*n matrix H, we have that Hv is orthogonal to z : 我知道b是對的 : c是錯的 : a d不太會選 a) 舉一個n = 2的情況為反例 let v = (1,0), z = (0,1), w = (2,0) H = [ 0 1 ] Hz = (1,0) 並沒有和 v,w 正交 [ 1 0 ] d) 我想是相同道理吧! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.243.149.202
compulsory:感謝 02/14 22:59
BenLinus:用幾何的角度來想, orthogonal matrix 就是旋轉的意思, 02/14 23:11
BenLinus:轉個角度, 也許就不垂直了 02/14 23:11
hunter0904:正交保角度 Hv Hz就會垂直 02/15 00:01
dy957:樓上說的其實也是保內積 02/15 00:14
BenLinus:嗯嗯, 一起轉某個角度, 相對好像沒轉一樣。 02/15 00:14
mmkuo:哦哦~ 所以這題如果說是Hv正交Hz的話就是Ture囉? 是嗎? 02/15 11:07
BenLinus:是的 02/15 12:18