推 kai5566:謝謝你 9527 03/04 22:54
※ 引述《kai5566 (中肯˙專業凱56)》之銘言：
: We want to compare the maximum bandwidth for a synchronous
: and asynchronous bus. The synchronous bus has a clock cycle time of 50 ns, and
: each bus transmission takes 1 clock cycle.The asynchronous bus requires
: 40 ns per handshake. The data portion of both buses is 32 bits wide.
: Find the bandwidth
: for each bus when performing one-word reads from a 220-ns memory.
: 我...完全不知如何下手
: 題目意思也不太懂......汗顏...
: 麻煩了>"<
同步
send addr花50ns
read memory花220ns
send data花50ns
total 320ns
所以maximum bus bandwidth = 32bit/320ns=12.5MB/s
非同步那七個步驟自己看講義或課本吧
第一步花40ns
2,3,4花max(40*3,220)=220ns
5,6,7花40*3=120ns
total 380ns
所以maximum bus bandwidth = 32bit/380ns=10.5MB/s
大概就這樣吧
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