推 lexa:head從track0移到track10要花10mili-seconds 從sector0 08/08 15:33
→ lexa:轉到sector 5 要轉半圈 (因為一track有10個sector) 08/08 15:33
→ lexa:故旋轉時間是 0.5/6000rpm = 0.5/100rps = 0.005s = 5 08/08 15:33
→ lexa: mili-seconds 所以共花 15 mili-seconds 08/08 15:33
consider a 6000 rpm disk, which is of one single head, 11 tracks, and 110
sectors in total. Let the seek time is linearly proportional to the number of
tracks traveled, and to move the head across one track takes 1ms. Suppose that
the current head position is at track 0, sector0. It takes ____ milli-seconds
to seek to track 10, sector 5.
(note that tracks and sectors are numbered from 0)
洪捷的解答給 10 + 5*10^(-6) ms
請問這個要怎麼算?
謝謝
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