[理工] [資結] call by value 與 call by address問題

[jim055006 (jim)]

program main(in,out)

procedure p(a,b,c)

   begin

     b=b+2;
     c=c*a;

begin

  m:=3;
  n:=4;

  p(m+n,m,m);
  print(m);

end.

-------------------------------------------------------------------
Show the printed value, if the referencing strategy is
Call-by-name and Call-by-address.

試問這題要如何分析??

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推 ceo890710:如果是Call-by-name的話應該是3 因為值並未被改到
→ ceo890710:Call-by-address的話我算是35 b=b+2會先將m+2
→ ceo890710:然後因為c的位置是傳m的address進去 所以改b的同時也會
→ ceo890710:改到c 最後a*c是7*5存回c也就是m的address 然後print(m)
→ ceo890710:不知道有沒有錯，有錯請指正~謝謝..
推 jackbll:同樓上想法
→ jim055006:我也同意一樓的見解...只是他答案給的卻是name為29