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There are k+1 coins in a box. The ith coin will, when flipped, turn up head with probability i/k,I=0,1,...k. A coin is randomly slected from the box and is then repeatedly flipped. If the first n flips all results in heads, what is the conditional probability that the (n+1)st flip will do likewise? 我的想法是 第n+1次和第n次的關係互為獨立 算出來答案是 n+1/k+1 但是答案是 k+1/2k 請高手幫忙解答一下 感謝... -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.184.192.244
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