[理工] [線代]矩陣應用

[dkcheng (電磁霸主)]

    [ 0 1 0 ]    A   [ a b c ]
A = | 0 0 1 | , e  = | d e f | , find a+b+c.
    [ 0 0 0 ]        [ g h i ]





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→ itsforte:jordan form eigenvalue三重根0  代一下公式就有了
→ dkcheng:可以用Cayley-Hamilton解嗎 ?
推 wheels:應該可以，f(x) = e^x = 1 + x/1! + x^2/2! + x^3/3! +...
→ wheels:因為A為nilpotent index為2，所以f(A) = I + A/1! + A^2/2!
推 harrypotter2:可以用Cayley-Hamilton