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A 80Mev photon is elastically scattered by a proton that is at rest what's the max possible energy loss for the photon (the compton wavelenth of electron is 2.4 X10^-12) Ans.68.5Mev 算了老半天算不出來 哭哭 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.47.175.244
cg1436:我算出來E'=68.34Mev,△E=11.66Mev 11/12 12:27
cscscscs22:怎麼算大大0.0 這是選擇題 答案很接近 11/12 12:33
cg1436:E'=pc/(1+(2pc/Mc^2)) pc=hv=80Mev Mc^2=938Mev 11/12 12:45
cscscscs22:這哪招...我以為會用到λ'-λ= λc(1-cosθ) 11/12 12:50
cscscscs22:再用12400/λ 去轉換 11/12 12:51
cg1436:上面那個就是用你說的導出來的阿 我早上沒時間導給你看而已 11/12 21:24