看板 Grad-ProbAsk 關於我們 聯絡資訊
※ 引述《bizzard (EGG)》之銘言: : 題目:http://ppt.cc/1c2x : 問題: 框框部份 a小題該怎嚜解? x + y + z = 0 => z = - x - y 2 2 2 代入 x + y + z = 1 2 2 2 2 x + y + x + 2xy + y = 1 ┌ ┐T┌ ┐┌ ┐ |x| | 2 1 ||x| | | | || | = 1 |y| | 1 2 ||y| └ ┘ └ ┘└ ┘ det(λI - A) = 0 |λ-2 -1 | | | | | = 0 | -1 λ-2| 2 λ - 4λ + 3 = 0 λ = 1、3 ┌ ┐T┌ ┐┌ ┐ |x'| | 1 0 ||x'| =>| | | || | = 1 |y'| | 0 3 ||y'| └ ┘ └ ┘└ ┘ 2 2 x' + 3y' = 1 1 => a = 1、b = --- √3 π S = πab = --- √3 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.112.44.41
bizzard:可是詳解上面是π 11/28 22:43
ocean5566:詳解可能是錯的 11/28 23:13