看板 Grad-ProbAsk 關於我們 聯絡資訊
E={u1,u2,u3} , F= {b1,b2} u1=(1,0,-1)^t u2=(1,2,1)^t u3=(-1,1,1)^t b1=(1,-1)^t b2=(2,-1)^t L(X)=(X1+X2,X1-X3)^t from R3 to R2 find representing L with respect to the order base E and F 可以這樣解嗎 [1 2]^-1 [1 1 0] [ 1 1 1] [-1 -1] [1 0 -1] [ 0 2 1] [-1 1 1] -- When we toss a coin , we obtain either head or tail. Now we toss a coin 5 times. There are 2^5 possible outcomes. How many of them contain no two consecutive heads? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 59.105.81.56
JiDung:不是本來就這樣解嗎@@ 02/02 22:23
Jerrynet:yes 02/02 22:29
bjk:我怎麼解出來答案不對QQ 02/02 22:32
mp8113f:ok吧 矩陣最後一個元素是-1 是你打錯嗎 還是抄錯 02/02 22:35
抄錯了,難怪都算錯 [1 2]^-1 [1 1 0] [ 1 1 -1] [-1 -1] [1 0 -1] [ 0 2 1] [-1 1 1] [-5 -3 4] [ 3 3 -2] ※ 編輯: bjk 來自: 59.105.81.56 (02/02 22:44)
bjk:有人有算嗎,這樣對嗎? 02/02 22:44
mp8113f:你不要計算錯誤 就是答案了 0.0 02/02 22:49
bjk:恩恩 3QQ 02/02 23:08
Demonic221:想請問這種算法是用換底公式嗎? 不是很懂@@" 02/03 00:00