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※ 引述《tedmax100 (tedmax)》之銘言: : A secret agency simultaneously monitors 150 cellular phone conversations and : multiplexes the data onto a network with a bandwidth of 5 MB/sec and an : overhead latency of 150 μs per 1 KB message. : Calculate the transmission time per message and determine whether there is : sufficient bandwidth to support this application. : Assume that the phone conversation data consists of 2 bytes sampled : at a rate of 4 KHz. : 想問問這題 這問題是有兩個答案嗎? 計算每個訊息的傳遞時間 跟 定義頻寬嗎? : 請問怎解@@" : 第一個時間 是 4KHz*2byets*150 conversations = 1200Kbytes ? : 接著要怎下去 ---------------------------------------------------------------------------- 接著算出 Trasmission time per 1KB =transmission time + overhead latency time 最後算出 Total time required to monitor (sec)!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.40.204.20