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1.show that,if Y=g(X),g is deterministic function,then H(g(X)|X)=0. 2.H(X|g(X))=0,this means the value g(X) uniquely determine X,or that g() is a one-to-one mapping. how to solve this problem? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.70.141.92