→ BaaaSwin:第8提把u拆成u1跟u2,分別用特徵函數展開法,或者重疊定理 12/13 17:40
→ BaaaSwin:一次算 12/13 17:40
推 BaaaSwin:2.你把y2=uy1代進去可以整理出u''+u'[(2y1')/y1+p]=0 12/13 17:48
→ BaaaSwin:令u'=U-->U'+U[(2y1'/y1)+p]=0做一階線性 12/13 17:50
→ BaaaSwin:就有答案咧 12/13 17:50
→ BLUEBL00D:第2題ZILL CULLEN課本內有證明 12/13 22:20