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assume we are designing a 16bit mips cpu with 16 bit instruction words. (1)assume the ieee-754 floating-point representation is also adjusted to 16bit long for this 16bit mips cpu. if the floating-point numbers are required to represent the values within ±10^18 , what are the numbers of bits of the feilds (a)(b)(c) in this 16 bit floating-point format? please your reasons,(assume log 2 = 0.3 ) 10 sign exponent mantissa (a) (b) (c) 請問: (b) 6bit (c) 9bit 怎麼來的。 謝謝… -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.252.158.162
BaaaSwin:表示範圍10^18內->2^60內->Exponent=6->mantissa=16-1-6 12/21 23:41
VB2005:2^60內->Exponent=6 可以再說明一下嗎? 12/21 23:44
Bearcome:2^6=64 你只需要60 12/21 23:58
VB2005:哦~~了解。謝謝 12/21 23:59
BaaaSwin:6個Exponent可以表達到2的-30~31次方! 12/22 00:37
Murasaki0110:請問, 可是題目要求不是要到2^60 12/22 12:11
BaaaSwin:不是表達的數要在2^60以內嗎@@?還是我誤會了 12/22 12:41
BaaaSwin:我想說如果7bit表達的數就超過2^60了 12/22 12:42