Re: [理工] 常係數線性ODE

[Honor1984 (希望願望成真)]

※ 引述《xoo1208 (RaInBoW)》之銘言：
: Solve ： d^2y/dt^2 - 4dy/dt + 4y = 3e^-t + 2t^2 + sint
: 求解 Yp =

1/(D-2)^2 (3e^(-t)) = 3e^(-t)/9 = (1/3)e^(-t)


1/(D-2)^2 2t^2 = [1/4 + D/4 + 3D^2/16]2t^2 = t^2/2 + t + 3/4

                     3sint + 4cost
1/(D-2)^2 sin(t) =  ------------------
                        3^2 + 4^2

--
※ 發信站: 批踢踢實業坊(ptt.cc) 
◆ From: 128.220.159.5
推 xoo1208:謝謝大大~~