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※ 引述《eric820715 (Eric)》之銘言: : http://i.imgur.com/1dYaVnr.jpg請問這題laplace轉微分方程到這個地方怎麼化簡的呢? : http://i.imgur.com/xwGuwkK.jpg謝謝~ 1 ------------------- s^2[s^2 + 2s + 2] 1 = ------------------ s^2[(s+1)^2 + 1] A B Ds + E = ---- + ------ + ------------- s s^2 (s+1)^2 + 1 A + D = 0 B = 1/2 5A + 5B + D + E = 1 => 5A + D + E = -3/2 => 4A + E = -3/2 -A + B - D + E = 1 => -A - D + E = 1/2 => E = 1/2 => A = -1/2 => D = 1/2 1 ------------------- s^2[s^2 + 2s + 2] 1 = ------------------ s^2[(s+1)^2 + 1] (-1/2) 1/2 (1/2)[s + 1] = ---- + ------ + ------------- s s^2 (s+1)^2 + 1 -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 61.228.134.142 ※ 文章網址: http://www.ptt.cc/bbs/Grad-ProbAsk/M.1399475621.A.CB5.html