看板 Grad-ProbAsk 關於我們 聯絡資訊
※ 引述《xoo1208 (RaInBoW)》之銘言: : Ex: 4xy+6y^2+(2x^2+6xy)y'= 0 (2xy + 3y^2)dx + (x^2 + 3xy)dy = 0 μ = x^a y^b 2(1 + b) x^(a + 1) y^b + 3(2 + b)x^a y^(b + 1) = (2 + a)x^(a + 1) y^b + 3(a + 1)x^a y^(b + 1) => 2b = a 1 = a - b => b = 1 a = 2 => μ = x^2 y => (2x^3 y^2 + 3x^2 y^3)dx + (x^4 y + 3x^3 y^2)dy = 0 Ψ = (1/2)x^4 y^2 + x^3 y^3 = C' => x^4 y^2 + 2 x^3 y^3 = C -- ※ 發信站: 批踢踢實業坊(ptt.cc), 來自: 220.141.67.61 ※ 文章網址: http://www.ptt.cc/bbs/Grad-ProbAsk/M.1411583515.A.DDF.html