→ yuyol:哎呀,被吐槽了XD 推 140.112.248.37 02/24
→ yuyol:必存在一條線,使得所有非該線交點都在同側 推 140.112.248.37 02/24
→ yuyol:考慮所有跟該線共邊的三角形, 推 140.112.248.37 02/24
→ yuyol:分析剩下n-1條線中任取兩線與該線交角關係 推 140.112.248.37 02/24
→ yuyol:得 f(n) = f(n-1) + [n/2]*(n-1-[n/2]) 推 140.112.248.37 02/24
→ yuyol:這樣應該沒錯....吧 XD 推 140.112.248.37 02/24
→ yuyol:f(n) = f(n-1) + [n-1/2]*(n-1-[n-1/2]) 推 140.112.248.37 02/24
→ yuyol:獻醜了 推 140.112.248.37 02/24