看板 IMO_Taiwan 關於我們 聯絡資訊
1. x=y=0: f(0)=f(0)[f(0)] f(0)=0 or [f(0)]=1 If [f(0)]=1, then x=0: f(0)=f(y)[f(0)]= f(y), f is constant C, with 1<=C<2 x=y=1: f(1)=f(1)[f(1)] f(1)=0 or [f(1)]=1 If f(1)=0, then x=1 f(y)=f(1)[f(y)] = 0, f=0 The remaining case is f(0)=0, [f(1)]=1 In this case, y=1: f([x])=f(x) But x=2, y=0.5: 1 <= f(1) = f(2)[f(0.5)] = 0, contradiction. -- r=e^theta 即使有改變,我始終如一。 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 217.196.27.186
LPH66:最後一個 = 我愣了兩下才看懂是 f(0.5)=f([0.5])=f(0)=0... 07/10 01:36
※ 編輯: LimSinE 來自: 61.62.72.252 (07/15 21:34) ※ 編輯: LimSinE 來自: 61.62.206.62 (07/26 00:34)