Re: [討論]矩陣分解 用for loop

[cmjer (民J)]

A=magic(8);
n=1;
for i1=1:(8/2)
    for i2=1:(8/2)
       M{n}=A(2*(i1-1)+1:2*i1,2*(i2-1)+1:2*i2);
       n=n+1;
    end
end


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◆ From: 140.117.167.222
※ 編輯: cmjer           來自: 140.117.167.222      (05/22 19:47)
→ simon0216117:感謝cmjer的解惑,讓我開始對程式有信心了,感謝!感謝!