Re: [問題] 迴圈

[james1022jk (雁)]

※ 引述《icrtstyle (嘿嘿)》之銘言：
:    我想請問一下,要怎麼把以下3個迴圈合併在一起????
: ----------
: for i=1:n;
:     t=1;
:     x(i,t+1)=x(i,t)+g(i,t);
:     for j=1:n;
:         x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1);
:     end
: end
: for i=1:n;
:     t=2;
:     x(i,t+1)=x(i,t)+g(i,t);
:     for j=1:n;
: x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1)+e*(exp(-1))*aa(i,j)*(x(j,t-1)+g(j,t-1));
:     end
: end
: for i=1:n;
:     t=3;
:     x(i,t+1)=x(i,t)+g(i,t);
:     for j=1:n;
: x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1)+e*(exp(-1))*aa(i,j)*(x(j,t-1)+g(j,t-1))+
:                                      e*(exp(-2))*aa(i,j)*(x(j,t-2)+g(j,t-2));
:     end
: end
: -----------------------------


for t = 1:3
    for i = 1:n

        x(i,t+1) = x(i,t)+g(i,t);

        for j = 1:n

            switch t
                case 1
                   x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1);

                case 2
                   x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1)+...
                            e*(exp(-1))*aa(i,j)*(x(j,t-1)+g(j,t-1));
                case 3
                   x(i,t+1)=x(i,t+1)+e*aa(i,j)*x(j,t+1)+...
                            e*(exp(-1))*aa(i,j)*(x(j,t-1)+g(j,t-1))+...
                            e*(exp(-2))*aa(i,j)*(x(j,t-2)+g(j,t-2));
            end
       end
    end
end

我果然是太無聊..........................................................

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推 icrtstyle:感謝~~~不過,如果我要做t到20,這樣不就很麻煩了~~~
→ icrtstyle:其實我是要做t到100,所以想請各位看有沒有方法解決