[分析] 初微(16)

[PttFund (批踢踢基金)]

Let p, q > 1 with 1/p + 1/q = 1. Show that

        ab ≦ a^p/p + b^q/q

where a and b are nonnegative.


Note: 這個就是 Holder inequality, 然後請不要用 Young's inequality
      來證明.


--
※ 發信站: 批踢踢實業坊(ptt.cc) 
◆ From: 140.112.218.142