→ theoculus :AP˙AB = 0.5 * AB^2 ; AP˙AC = 0.5 * AC^2 12/27 22:24
→ theoculus :AH˙AB = AB˙AC = AP˙AC 12/27 22:24
→ theoculus :分別對 AB、AC向量作內積吧 12/27 22:25
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已知BC=6,CA=2√7,AB=4,
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1.設P為ΔABC之外心,令AP=xAB+yAC,求x,y之值
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2.設H為ΔABC之垂心,令AH=xAB+yAC,求x,y之值
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