[微積] 極限計算

[monemo13 (李孟李孟)]

        1+sin(x-3π/2)
1. lim  ═══════  = ?
  x→π     x-π


                2
         (x-π/4)
2. lim   ═══  2 = ?
 x→π/4 (tanx-1)

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◆ From: 123.0.235.49
推 jameschou   :1.答案是0 , 2.答案是1/4
→ monemo13    :為什麼呢?
→ monemo13    :答案是對的
推 jameschou   :羅必達呀  分子分母同為0就分子分母都微分
→ monemo13    :對吼...我太侷限於章節了...謝謝！
→ theoculus   :1+sin(x-3π/2) = sin((x-π)-π/2) - sin(-π/2)
→ theoculus   :tanx-1 = tanx - tan(π/4)
→ jacky7987   :樓上方法好酷