[線代] 三角函數sin的對角化

[mqazz1 (無法顯示)]

        [ -1  1  1 ]
let A = [  2 -2 -3 ]
        [ -2  2  3 ]

a = sin(1)

find sin(A^2001) = ?


請問這題要怎麼解?

我已經求出

            [  1  1  0 ]                 [  1 -1 -1 ]
可逆矩陣P = [ -1  1 -1 ]        P^(-1) = [  0  1  1 ]
            [  1  0  1 ]                 [ -1  1  2 ]

            [ -1  0  0 ]
對角矩陣D = [  0  0  0 ]
            [  0  0  1 ]

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