(=>)
Suppose an mxn matrix A satisfies rank(A)=1 , then
[a1]
[a2]
A= [ .] , where ai is ith row vector of A (ai is an 1xn matrix)
[ .]
[am]
since rank(A)=1 , thus
[ 1*a1] [ 1]
[c2*a1] [c2]
A= [ . ] = [ .] a1 = BC
[ . ] [ .]
[cm*a1] [cm]
逆推感覺很像把我寫的反回去 自己試試看吧
--
我可以為兄弟兩肋插刀，
但我可以為女人插兄弟兩刀。
--
※ 發信站: 批踢踢實業坊(ptt.cc)
◆ From: 140.113.90.84