推 G41271 :這不就是橢球嗎 02/06 15:06
→ simmy420 :阿...我懂了,謝謝 02/06 15:21
題目: Find the volume of the solid bounded by the surface x^2+3*y^2+z^2=1
想到要用極座標 x=rcosθ , y=rsinθ
(rcosθ)^2+3(rsinθ)^2+z^2=1
=> r^2(1+2(sinθ)^2)+z^2=1
=> z= ±√(1-r^2(1+2(sinθ)^2))
然後就卡住了...
請問該如何計算呢?
謝謝
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