推 asynchronous:這是兩個圓. 正交的條件是 r1^2 + r2^2 = (O1O2)^2 02/22 01:07
x^2 + y^2 + d_1*x + e_1*y + f_1 = 0
x^2 + y^2 + d_2*x + e_2*y + f_1 = 0
若正交
證：d_1*d_2 + e_1*e_2 = 2*(f_1+f_2)
我看不懂題目 = ="
請大大解說...
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