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這一個證明的過程有一個點不懂 L:R^n --> R^m with the two bases E=[u1,,,,,,un] F=[b1,,,,,,,,bn] then the reduced row echelon form of (b1,,,,,,,bm | L(u1),......L(un)) is (I|A) -_____________________________________________________________________ PROOF: Let B=(b1,,,,,,,,bm). The matrix (B | L(u1),,,,,,,,,,L(un)) is row equivalent to B^-1 ( B | L(u1),,,,,,,,,L(un) 我想問的是為什麼前面乘一個B的反矩陣仍然會row euqivalent -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 140.116.117.15
znmkhxrw :應該是因為B是basis 寫成n by n後的determinant不為0 02/25 00:30
znmkhxrw :所以B^-1也是 02/25 00:30
skyhigh8988 :謝謝您^_^我懂了 02/25 16:56