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※ 引述《Bourbaki (大狐狸)》之銘言: : dx : ---- = x(y^2 + 1) : dt : dy : ---- = -y(x^2 + 1) : dt : 請問該怎麼解呢 : 謝謝^^ dy/dx=-y(x^2+1)/x(y^2+1), this is separable but this only solve the solution curve in terms of x and y, as for how to parameterize it? u can think about it. at least one is the function of the other locally. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.217.146.182
rockflying :兩式相除可解得, x^2+y^2+2ln(xy)=c 的族 03/08 01:10
Bourbaki :感謝 雖然似乎沒辦法解出x(t)和y(t) 不過已經好多了 03/08 01:37