推 math1209 :Dini thm 04/12 16:22
→ bineapple :Got it. Thx! 04/12 16:32
推 ppia :(1+x/n)^n = [(1+x/n)^(n/x)]^x, 計x/n=α 04/13 11:30
→ ppia :已知(1+1/α)^α 隨 α 遞增至 e 04/13 11:31
→ ppia :給定 ε>0, 存在δ>0 使得 只要 0 < x/n < δ 04/13 11:34
→ ppia :我們就有 (1+x/n)^(n/x) > 1 - ε 04/13 11:35
→ ppia :打錯 ">e-ε" 04/13 11:35
→ ppia :因此, (1+x/n)^n > e^x(1-xε/e) ≧e^x(1-aε/e) 04/13 11:37
→ ppia :只要 n > a/δ 04/13 11:37