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Let Xn be the sum of the first n outcomes of tossing a six-side die repeated in an independent fashion. Compute P(Xn is dibisible by 7) as n->∞ 先謝謝各位了!! -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 61.227.195.16
KitWoolsey :1/7 05/08 22:37
KitWoolsey :if Xn-1 is divisible by 7 --> Xn is not 05/08 22:39
KitWoolsey :Xn-1 is not --> Xn has 1/6 chance div by 7 05/08 22:39
KitWoolsey :so f(n) = {1-f(n-1) }/6 05/08 22:39
KitWoolsey :so f(n) = 1/7 if it is to be stable 05/08 22:40