推 horse5566lee:第二招很棒@@ 05/27 00:48
※ 引述《TVBS2100 (濤歌的節目)》之銘言:
: http://imageshack.us/photo/my-images/36/fffdffd.jpg/
: 我將原式算到這之後就卡住了
: 懇請解答
[I]
2 2x
∫x e dx
1 2 2x
= ---∫x d(e )
2
1 2 2x 2x
= ---x e - ∫xe dx
2
1 2 2x 1 2x
= ---x e - ---∫xd(e )
2 2
1 2 2x 1 2x 1 2x
= ---x e - ---xe + ---∫e dx
2 2 2
1 2 2x 1 2x 1 2x
= ---x e - ---xe + ---e
2 2 4
[II]
2 2x
∫x e dx
1 2 2x
= ---x e
D
2x 1 2
= e -----x
D+2
2
2x 1 D D 2
= e (--- - --- + --- - ...)x
2 4 8
2x 1 2 1 1
= e (---x - ---x + ---)
2 2 4
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