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※ 引述《alasa15 (alasa)》之銘言: : Evaluate : ∫∫∫ (x^2+y^2)^0.5 dV, where B is the volumn bounded by z=x^2+y^2 : B and z=4 : I do this problem in two ways, but i got two different answers. : Method I. ∫∫ (x^2+y2)0.5 * [4-x^2-y^2] dxdy : D : Method II. Let x=r cost, y=r sint, z=z => |J| = r : 2π 2 2 : ∫ ∫ ∫ (r^2)^0.5 * r dy dr dt : 0 0 0 : which is correct? : (I think there are some mistakes in Method II..) Yeah, Method II got a little mistake, your "z" interval is wrong in yours , the volume just means "cylinder" but the correct one is z = r^2 ~ 4 you can try to draw a picture when you not sure. Or you can put x=rcost , y = r sint inside the condition and you will get. z = r^2 and z = 4 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 114.34.122.244 ※ 編輯: rygb 來自: 114.34.122.244 (07/07 12:36)
alasa15 :THANKS A LOT! 07/07 12:51