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※ 引述《CFE220 (五行之友)》之銘言: : Find the limit : x{[(x^2+1)^1/2]-[(x^3+1)^1/3]} when x → +∞ Let x^2+1=A, x^3+1=B. Then the original statement = x(A^1/2-B^1/3) = x(A^3-B^2)/{[A^1/2+B^1/3]*[A^2+A*B^2/3+B^4/3]}. Replace A and B by x^2+1 and x^3+1 and divide the numerator and the dominator by x^4, then we get that the limit is 1/2. : Determine the series : ∞ : Σ {[(n^2+1)^1/2]-[(n^3+1)^1/3]} : n=1 By the last problem we know that the summand is a big O of 1/n as n→∞, so the series grows as fast as the harmonic series, which diverges. Thus this series diverges. -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 123.192.216.62 ※ 編輯: bineapple 來自: 123.192.216.62 (07/08 00:36)