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Let A be an n*n matrix over R such that A^5=I .Here, as usual, I denotes the identity matrix. Show that if the trace tr(A)=0 , then Av=v holds, for some non-zero vector v 似乎有在教科書出現過,不過還是不會.. 希望有人能解迷津或給個答題的方向, 感謝感謝。 -- -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 218.166.112.125
LiamIssac :eigenvalue? 07/14 13:51
zyjheng :consider minimal polynomial, since over R, 07/14 13:53
zyjheng :1 should be an eigenvalue. 07/14 13:53