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A closest cylindrical can is to hold 500cm^3 of liquid , how should we choose the height and radius to minimize the amount of material needed to manufacture the can? -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 111.249.93.31
ntust661 :目標函數 07/26 22:57
ntust661 :pi*r^2*h = 500 07/26 22:57
ntust661 :f(A) = 2*pi*r^2 + 2*pi*r*h 07/26 22:58
ntust661 :h = 500/pi/r^2 07/26 22:59
ntust661 :代入 f(A) 07/26 22:59
ntust661 :f(A) 就會變成 f(r) 07/26 22:59
ntust661 :若表面積要最小,至少一階導數要等於零 07/26 22:59
ntust661 :f'(r) = 0 , find r 07/26 23:00
ntust661 :then calculate h 07/26 23:00
FoggyCloud :thanks! 07/26 23:19
young11539 :CHECK f''(r)>0 07/27 01:34