看板 Math 關於我們 聯絡資訊
※ 引述《wheniam64 (嘿)》之銘言: : 1. Suppose that an →L. Show that if an 小於等於 M for all n, : then L 小於等於 M .   For any ε > 0, we have L–ε < a ≦ M for some n, so L ≦ M. n (If a–ε < b for any ε > 0, then a ≦ b.) : 2. Let f be a function continuous everywhere and let r be a real number. : Define a sequence as follows: : a1=r , a2=f(r) , a3=f(f(r)) , ......... : Prove that if an→L, then L is a fixed point of f:f(L)=L   Note that a = f(a ). n+1 n L = lim a = lim f(a ) = f(lim a ) = f(L). n→∞ n+1 n→∞ n n→∞ n f is continuous. [Extension]   Moreover, if │f'(x)│< 1, for all x in [a,b] then 1. f has one and only one fixed point on [a,b]. 2. {a } converges to the fixed point for any r in [a,b]. n : 這二題習題和同學討論許久不得其解 : 請版上高手解答 : 感謝! -- 【板主:dishpan/hayamavic/elisama】第十四屆小天使招生中 看板《NewAngels》 作者 NTUSTking (洪興帥哥 山雞) 站內 NewAngels 標題 [新生] NTUSTking
NTUSTking:先別TEST 等下我要去夜店 125.230.207.63 08/17 23:06
-- ※ 發信站: 批踢踢實業坊(ptt.cc) ※ 編輯: Minkowski 來自: 140.123.62.134 (08/17 23:51)
wheniam64 :感謝!! 竟然有 Minkowski XDD 08/17 23:55