推 wyob :感謝 08/30 17:24
※ 引述《wyob (Go Dolphins)》之銘言:
: y=x^2 , y=2^x
: 想請問這兩個的交點有幾個
: 應該用均值定理嗎???
: 我只找到兩個而已
: 所以想請問一下怎麼解
: 感謝
2 x
Let f(x) = x and g(x) = 2 . It is okay that f,g are both in
2
C (|R). Note that if f(α) = g(α) and f(β) = g(β) for some α < β,
then (f-g)(α) = (f-g)(β) = 0, by mean value theorem, there is a c in
(α,β) such that (f-g)'(c) = 0. Now, since
2 x
(f-g)"(x) = (㏑2) 2 - 2 = 0 has only one solution, (f-g)'(x) = 0 has
at most two solution, (f-g)(x) = 0 has at most three solution.
Now, we know that x = 2, 4 are solutions. In fact, since
1
(f-g)(-1) = ── and (f-g)(0) = -1, there is a solution between
2
-1 and 0. Exactly three solution.
[Supplyment Problem]
y x
Find integers x, y such that x = y .
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※ 編輯: Minkowski 來自: 140.123.62.134 (08/30 17:24)