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(1) h(4) = h(2+2) = g(2+1) = g(3) = g(7-4) = f(7+1) = f(8) = 8^2+2*8-3 = 77 (2) f[g(x)] = [g(x)]^3-2*[g(x)]+3 = (x-1)^3-2*(x-1)+3 = x^3-3x^2+x+4 f(2) = 2^3-2*2+3 = 7, g(7) = 7-1 = 6 -- ※ 發信站: 批踢踢實業坊(ptt.cc) ◆ From: 175.180.94.244
feishunhui :感謝再感謝 09/18 23:08