[微積]

[AAJJBurnett (叫我投手)]

       2
 試求 ∫x^2(1-x)^23 dx =
       0

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→ bibo9901    :let u=1-x, x^2(1-x)^23 dx = -(1-u)^2 u^23 du =...
→ AAJJBurnett :謝謝樓上  懂了~