推 Frobenius :Sum[2^(k - n) (k + n)!/n!, {n, 0, k}] 10/20 21:04
→ Frobenius : = 4^k (2 k! - Gamma[1 + k]) By Mathematica 8.0 10/20 21:04
→ jacky7987 :竟然還有closed form XD 10/20 21:06
推 Frobenius :Sum[2^(k-n)(k+n)!/n!,{n,0,k}]//FullSimplify 10/20 21:45
→ Frobenius : = 4^k Gamma[1 + k] = 4^k k! By Mathematica 8.0 10/20 21:46
推 sarsenwen :Mathematica good 10/20 21:55
推 TrySoHard :matlab應該也可以 10/21 11:52
推 sunev :只要是程式幾乎都可以,excel也行 10/21 12:54
→ fiveupboy :謝謝各位大大^^ 10/25 10:25